intellij Spring MVC & Gradle 프로젝트 생성

프로그래밍/Spring

intellij Spring MVC & Gradle 프로젝트 생성

은바재바 2020. 5. 22. 15:46

1. gradle 선택 -> java, web 체크

2. build.gradle에 소스 추가

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apply plugin: 'war'
 
providedCompile 'javax.servlet:servlet-api:2.5'
    compile 'org.springframework:spring-webmvc:5.0.6.RELEASE'
    runtime 'javax.servlet:jstl:1.1.2'

3. webapp 아래에 web.xml, dispatcher-servlet.xml, applicationContext.xml 파일 생성 & views폴더 생성 후 index.jsp파일 이동

<web.xml>

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd"
         version="4.0">
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/applicationContext.xml</param-value>
    </context-param>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
</web-app>

< dispatcher-servlet.xml >

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<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:mvc="http://www.springframework.org/schema/mvc"
       xsi:schemaLocation="http://www.springframework.org/schema/beans 
        http://www.springframework.org/schema/beans/spring-beans.xsd 
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd 
        http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">
 
    <mvc:annotation-driven />
    <context:component-scan base-package="com.spring.controller" />
    <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/views/"/>
        <property name="suffix" value=".jsp"/>
    </bean>
</beans>

<applicationContext.xml >

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

</beans>

4. projectStructure에서 artifacts 추가

5. 톰캣 설정

6. index.jsp과 JdbcController.java 생성

< index.jsp >

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<%--
  Created by IntelliJ IDEA.
  User: choej
  Date: 2020-05-22
  Time: 오후 2:48
  To change this template use File | Settings | File Templates.
--%>
<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
  <head>
    <title>$Title$</title>
  </head>
  <body>
  ${msg}
 
  </body>
</html>
 

< JdbcController.java >

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package com.spring.jdbc;
 
import java.sql.*;
 
public class JdbcController {
    public static void main(String[] args) {
        try {
            Connection conn = DriverManager.getConnection(
                    "jdbc:mariadb://localhost:3306/project",
                    "eunbajaeba",
                    "qw0e7r2t2!"
            );
 
            Statement stmt = conn.createStatement();
            ResultSet rs = stmt.executeQuery(
                    "select * from t_member"
            );
 
            while (rs.next()) {
                System.out.println(rs.getString(1));
            }
        } catch (SQLException e) {
            e.printStackTrace();
        }
    }
}

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